Home » discuss » Public forums » Developing for iMIS

Asi.Security.appPrincipal.CurrentIdentity.ContactMaster returns empty string

Posted November 5th, 2009 by Steve Russell
|

I am trying to pull the currently logged on member's iMIS ID following the Guidlines for Developing iParts from the Innovations Converence (sepcifically duplicating the GetCurrentiMISID method:

public string GetLoggedinIMISID()
{
string _id = "";
try
{
if (Asi.Security.AppPrincipal.CurrentIdentity.IsAuthenticated && Asi.Security.AppPrincipal.CurrentIdentity.ContactMaster != "")
{
_id = Asi.Security.AppPrincipal.CurrentIdentity.ContactMaster;
}
}
catch { }
return _id;
}

I don't get any compile or runtime errors, it just returns blank values.  I am trying to read from a custom table and just display data in a datagrid.  This is 15.0.3 if that matters.  It is an aspx page with code behind.   Any thoughts/help would be greatly appreciated.  I am losing my hair fast enough as it is, thank you.

‹ Database Error IQA Drilldown ›
login or register to post comments | printer friendly version

Comment viewing options

Select your preferred way to display the comments and click "Save settings" to activate your changes.

Use SessionState in ContentManagerNet assembly..

On November 5th, 2009 nmuhammad says:

Im presuming this is in eCM .net.

If it is, then we have always used the following:

CContactUser contactUser = Asi.ContentManagerNet.SessionState.User;

The SessionState object usually contains logged in status as well.

Nasser

login or register to post comments

Actually, no, it is not. 

On November 5th, 2009 Steve Russell says:

Actually, no, it is not.  This is 15.0.3 without eCM or WCM, public views.

login or register to post comments

In 15.0.3 your code won't

On November 5th, 2009 Eric Means says:

In 15.0.3 your code won't work; it will work on the web view, for Casual/Full users, but not for public users. Nasser's code will work fine (even without eCM/WCM), and should carry forward to 15.1+ without any changes as well.

Eric Means
System Architect, ASI

login or register to post comments

Thanks.  But I need more

On November 5th, 2009 Steve Russell says:

Thanks.  But I need more assistance please.  I know, trying to teach an old dog new tricks can be a challenge.  How do I assign that output of that to my variable _id so I can use it to construct the where clause in my sql? 

login or register to post comments

Simple Sample :)

On November 5th, 2009 Eric Means says:

if (Asi.ContentManagerNet.SessionState.IsLoggedIn)
    _id = Asi.ContentManagerNet.SessionState.User.ContactId;

Eric Means
System Architect, ASI

login or register to post comments

Thanks!  I was missing the

On November 5th, 2009 Steve Russell says:

Thanks!  I was missing the .ContactId!  Guess that helps!

login or register to post comments